Reaction Mechanisms
What is a reaction mechanism?
- Most reactions do not occur in one step but in a series of simple steps
- Each step is called an elementary step and involves a small number of particles
- Some of the products of an elementary step exist as intermediates and react in subsequent steps
- The sequence of elementary steps is called the reaction mechanism
- The sum of the elementary steps must equal the overall reaction equation
- Intermediates that are produced in one elementary step and react in another step cancel out
- Chemical kinetics can only suggest a reaction mechanism, they cannot prove it
- However, they can be used to disprove a proposed mechanism
- Elementary steps are the steps involved in a reaction mechanism
- For example, in the following general reaction:
A + B → C + D
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- The elementary steps could involve the formation of an intermediate:
Elementary step 1: A → R + D
Elementary step 2: R + B → C
- It is important that the elementary steps for a proposed mechanism agree with the overall stoichiometric equation
- For example, combining the 2 elementary steps above gives the overall stoichiometric equation
A + R + B → R + C + D
A + B → C + D
Worked example
Sulfur dioxide reacts with oxygen to form sulfur trioxide
- Propose a one-step mechanism for the above reaction
- The above reaction is catalysed by the formation of nitrogen dioxide from nitrogen monoxide. Propose a two-step mechanism for this reaction.
Answer 1:
- A one-step reaction mechanism is simply the overall stoichiometric equation
- Therefore, the correct answer is 2SO2 + O2 → 2SO3
Answer 2:
- One of the two elementary steps for this two-step mechanism can be taken from the question:
- Elementary step 1: 2NO + O2 → 2NO2
- The second elementary step must involve the reaction of the nitrogen dioxide formed with sulfur dioxide:
- Elementary step 2: NO2 + SO2 → NO + SO3 (or 2NO2 + 2SO2 → 2NO + 2SO3)
Exam Tip
- It is important that you check the equations you are proposing for a reaction mechanism
- They must add up to the overall stoichiometric equation, otherwise the proposed mechanism is wrong.
What is the rate-determining step?
- A chemical reaction can only go as fast as the slowest part of the reaction
- So, the rate-determining step is the slowest step in the reaction
What does the rate equation tell us about the rate-determining step?
- If a reactant appears in the rate-determining step, then the concentration of that reactant will also appear in the rate equation
- The order with respect to a reactant describes the number of particles of that reactant that take part in the rate-determining step
Predicting the reaction mechanism
- The overall reaction equation and rate equation can be used to predict a possible reaction mechanism of a reaction
- For example, nitrogen dioxide (NO2) and carbon monoxide (CO) react to form nitrogen monoxide (NO) and carbon dioxide (CO2)
- The overall reaction equation is:
NO2 (g) + CO (g) → NO (g) + CO2 (g)
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- The rate equation is:
Rate = k [NO2]2
- From the rate equation, it can be concluded that the reaction is zero-order with respect to CO (g) and second-order with respect to NO2 (g)
- This means that there are two molecules of NO2 (g) involved in the rate-determining step and zero molecules of CO (g)
- A possible reaction mechanism could therefore be:
Step 1:
2NO2 (g) → NO (g) + NO3 (g) slow (rate-determining step)
Step 2:
NO3 (g) + CO (g) → NO2 (g) + CO2 (g) fast
Overall:
2NO2 (g) + NO3 (g) + CO (g) → NO (g) + NO3 (g) + NO2 (g) + CO2 (g)
Simplify (remove species on both sides of the equation):
NO2 (g) + CO (g) → NO (g) + CO2 (g)
Exam Tip
- It is important that the elementary steps for a proposed mechanism also agree with the experimentally determined rate equation
- The rate equation and the overall reaction must be related, i.e. the correct chemical species involved
- Remember: There is no direct link between the orders in the rate equation and the stoichiometry of the overall equation
- However, the rate equation can be derived directly from the rate-determining step and its stoichiometry
Predicting the reaction order & deducing the rate equation
- The order of a reactant and thus the rate equation can be deduced from a reaction mechanism if the rate-determining step is known
- For example, the reaction of nitrogen oxide (NO) with hydrogen (H2) to form nitrogen (N2) and water
2NO (g) + 2H2 (g) → N2 (g) + 2H2O (l)
- The reaction mechanism for this reaction is:
NO (g) + NO (g) → N2O2 (g) | fast |
Step 2:
N2O2 (g) + H2 (g) → H2O (l) + N2O (g) | slow (rate-determining step) |
Step 3:
N2O (g) + H2 (g) → N2 (g) + H2O (l) | fast |
- The second step in this reaction mechanism is the rate-determining step
- The rate-determining step consists of:
- N2O2 which is formed from the reaction of two NO molecules
- One H2 molecule
- The reaction is, therefore, second order with respect to NO and first order with respect to H2
- So, the rate equation becomes:
Rate = k [NO]2 [H2]
- The reaction is, therefore, third order overall
Exam Tip
- Intermediates in the mechanism cannot appear as substances in the rate equation
- Instead, the chemicals required to make the intermediate feature in the rate equation
- This is why you substitute the N2O2 in the above example
- Step 1 shows that 2NO molecules are required to form the necessary N2O2