Syllabus Edition

First teaching 2023

First exams 2025

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Standard Enthalpy Change (SL IB Chemistry)

Revision Note

Alexandra

Author

Alexandra

Expertise

Chemistry

Standard Enthalpy Change

  • The standard enthalpy change for a chemical reaction, ΔH, refers to the heat transferred at constant pressure under standard conditions and states
  • These standard conditions are:
    • A pressure of 100 kPa
    • A concentration of 1 mol dm-3 for all solutions
    • Each substance involved in the reaction is in its standard state (solid, gas or liquid)

  • Temperature is not part of the definition of standard state, but a temperature of 298 K (25 oC) is usually given as the specified temperature
  • To show that a reaction has been carried out under standard conditions, the symbol is used
    • Eg. ΔH = the standard enthalpy change

Standard Enthalpies

  • There are a few Standard Enthalpy changes which are used commonly in energy calculations and they are summarised below:

Standard Enthalpy
Change of ...
Definition
Symbol

Exothermic/

Endothermic

Reaction

The enthalpy change when the reactants in the stoichiometric equation react to give the products under standard conditions ΔHr
Both
Formation The enthalpy change when one mole of a compound is formed from its elements under standard conditions ΔHf
Both
Combustion The enthalpy change when one mole of a substance is burnt in excess oxygen under standard conditions ΔHc
Exothermic
Neutralisation The enthalpy change when one mole of water is
formed by reacting an acid and alkali under standard conditions
ΔHneut
Exothermic

 

  • Practice your understanding of enthalpy changes on the following worked examples:

Worked example

One mole of water is formed from hydrogen and oxygen releasing 286 kJ

H2 (g) + ½O2 (g)  H2O (l)             ΔHr= -286 kJ mol-1

Calculate ΔHr for the reaction below:

2H2 (g) + O2 (g)  2H2O (l)

Answer:

  • Since two moles of water molecules are formed in the question above, the energy released is simply:

ΔHr = 2 mol x (-286 kJ mol-1)

 = - 572 kJ

Worked example

Calculate ΔHr for the reaction below

4Fe (s) +O2 (g)    2Fe2O3 (s)

given that ΔHf  [Fe2O3 (s)]  = - 824 kJ mol-1

Answer:

  • Since two moles of Fe2O3 (s) are formed the total change in enthalpy for the reaction above is:

ΔHf =  2 mol x ( -824 kJ mol-1)

= - 1648 kJ

Worked example

Identify each of the following as  ΔHr, ΔHf, ΔHc or ΔHneut

  1. MgCO3 (s) MgO (s) + CO2 (g)
  2. C (graphite) + O2 (g)  CO2 (g)
  3. HCl (aq) + NaOH (aq)   NaCl (aq) + H2O (l)

Answers:

  • Answer 1: ΔHr
  • Answer 2: ΔHf as one mole of CO2 is formed from its elements in standard state and ΔHc as one mole of carbon is burnt in oxygen
  • Answer 3: ΔHneut as one mole of water is formed from the reaction of an acid and alkali

 

Exam Tip

You need to learn well the Standard Enthalpy change definitions as they are frequently tested in exam papers

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Alexandra

Author: Alexandra

Alex studied Biochemistry at Newcastle University before embarking upon a career in teaching. With nearly 10 years of teaching experience, Alex has had several roles including Chemistry/Science Teacher, Head of Science and Examiner for AQA and Edexcel. Alex’s passion for creating engaging content that enables students to succeed in exams drove her to pursue a career outside of the classroom at SME.