Syllabus Edition

First teaching 2023

First exams 2025

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Electron Sharing Reactions (SL IB Chemistry)

Topic Questions

1 hour18 questions
1a1 mark

There are three steps to the free radical substitution mechanism. When ethane and chlorine react in the presence of UV light, chloroethane is produced. Write the equation for the initiation step.

1b2 marks

Write two equations for the propagation steps for the reaction outlined in part (a).

1c1 mark

Write the equation using structural formulae for the termination reaction between two CH3CH2 free radicals.

1d1 mark

State the type of bond breaking that occurs in the initiation reaction to produce free radicals. 

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2a1 mark

State why a bromine atom can be described as an atomic radical.

2b2 marks
i)
Draw the Lewis formula for the ethyl radical.

[1]

ii)
Explain why this radical is not a long lasting species.
[1]
2c2 marks

State two conditions that are required to form a bromine radical from a bromine molecule.

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3a2 marks

State two reasons why alkanes are unreactive.

3b1 mark

Methane reacts with chlorine to produce chloromethane, CH3Cl. The reaction is initiated by the formation of chlorine radicals.

State the type of bond fission is involved in this reaction.

3c3 marks

Chloromethane will be formed via several steps.

i)
Write the equations for the two propagation steps.
[2]
ii)
Write an equation to show how ethane can be formed in this reaction.
[1]

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1a3 marks

Alkanes are generally unreactive and do not react with acids, bases, or with oxidising or reducing agents. However, they will react with halogens under suitable conditions, to form halogenoalkanes.

Methane reacts with chlorine in this way to form chloromethane.

i)
State the name of this type of reaction mechanism.
[1]
ii)
Write an overall equation for the reaction and give the reaction conditions.
[2]
1b3 marks

The reaction described in part (a) consists of three steps. In the first step, the Cl-Cl bond is broken to form two chlorine free radicals.

i)
State and explain the type of bond breaking that occurs in the initiation step. 
[1]
ii)
Define the term free radical
[1]
iii)
Explain why the C-H bond in the alkane does not break in the initiation step instead of the Cl-Cl bond. 
[1]
1c4 marks

Give the equations for each step of the reaction between methane and chlorine as described in part (a).

Label each equation with the name of the correct step. You only need to provide one equation for the final step.

1d4 marks

Chlorofluorocarbons (CFCs) are organic compounds consisting of carbon, chlorine, and fluorine atoms. They are believed to destroy the ozone layer in a similar reaction to the one described in part (a).

Ozone can be broken down by radicals formed in the atmosphere. The ozone layer is important to protecting the Earth from harmful exposure to ultraviolet light.
Without this ozone layer, life on Earth would be very different.

An example of a CFC which can damage the ozone layer is CCl3F.

i)
Explain why these free radicals act as catalysts in the breakdown of ozone to oxygen. Support your answer by writing suitable equations. 
[3]
ii)
Draw the three-dimensional structure of CCl3F and name the shape of the molecule. 
[1]

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2a4 marks

Trichloromethane is one of the products formed when dichloromethane reacts with excess chlorine in UV light.

i)
Name this mechanism.

[1]
ii)
Write equations for the initiation and propagation steps.

[3]

2b3 marks

Dichloromethane can also be formed in this reaction.

i)
Write the overall equation for the formation dichloromethane from chloromethane.
[1]
 
ii)
A compound was found to contain 20.3% carbon, 48.1% fluorine, 30.0% chlorine and 1.6% hydrogen. Calculate the empirical formula for this compound.
[2]
2c
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2 marks

Suggest the structural formula of two bromine containing compounds that are formed during the reaction of bromine and dibromomethane in the presence of UV light.

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3a4 marks

Consider the following reaction

RCH3 rightwards arrow with Cl subscript 2 comma space UV on topRCH2Cl

i)
The alkane contains 17.4% of hydrogen. Calculate the empirical formula of the alkane.
[3]
ii)
Equal volumes of methyl vinyl ether, CH3OCH=CH2 and the unknown alkane are found to have the same mass, measured to an accuracy of two significant figures, at the same temperature and pressure. Deduce the molecular formula of the alkane.
[1]
3b4 marks

The reaction in part a) involves a free-radical mechanism to form the chloroalkane.

Describe the mechanism, by giving equations to represent the initiation, propagation and termination steps.

3c1 mark

Draw the full displayed formula of the haloalkane formed if excess chlorine is used in the reaction in part a).

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1a2 marks

Dichloromethyl benzene reacts with chlorine to produce trichloromethyl benzene. State the name of this type of mechanism and the required condition. 

1b4 marks

Outline the mechanism for the reaction occurring in part a).

1c1 mark

A reaction pathway is shown below. Compound J reacts with bromine water to form a colourless solution.

10-2-ib-sl-sq-hard-q1c-compound-j


State the IUPAC name for Compound J.

1d2 marks

Identify the reagents and conditions for the formation of Compound Y from Compound J. 

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2a2 marks

For the reaction profile outlined in the reaction profile below, state the mechanism or type of reaction for steps 1 and 2. 

Propane rightwards arrow with Step space 1 on top 1-bromopropane begin mathsize 14px style rightwards arrow with Step space 2 on top end style Compound X rightwards arrow with Step space 3 on top Propanal 

Step 1 ...............................................................


Step 2 ...............................................................

 
2b3 marks

Compound X can be oxidised by the reaction with acidified potassium dichromate to give propanal. Compound X will oxidise to propanoic acid if allowed to fully oxidise. Explain how full oxidation can be prevented. 

2c4 marks

State the following for step 1.

Reagents and conditions ..........................................

Mechanism ..........................................

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3a2 marks

This question is about free radical substitution. 

1,2-dibromoethane reacts with bromine in UV light to produce a mixture of further substituted haloalkanes. 

i)
Write an equation for the initiation step. 
[1]
ii)
Explain why this is an example of homolytic fission. 
[1]

3b2 marks

Write two equations showing the propagation of this chain reaction to produce 1,1,2-tribromoethane. 

3c2 marks

Traces of 1,2,3,4-tetrabromobutane are found in the reaction mixture. 

i)
Write an equation to show how this product is formed. 
[1]
ii)
Write a balanced symbol equation to show the overall reaction between 1,1,2-tribromoethane with bromine in UV light to form hexabromoethane. 
[1]

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