Vector Equations of Lines (DP IB Applications & Interpretation (AI))

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Cards in this collection (13)

  • A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    What does the vector bold italic a represent?

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The vector bold italic a represents a position vector of any point on the line.

  • A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    What does the vector bold italic b represent?

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The vector bold italic b represents a direction vector.

  • True or False?

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The value of lambda determines where a point lies on the line.

    True.

    A vector equation of a line is bold italic r equals bold italic a plus lambda bold italic b.

    The value of lambda determines where a point lies on the line.

    lambda is similar to x in the equation of a line in 2D, y equals m x plus c.

  • True or False?

    For any line, there are an infinite number of ways of writing its equation in vector form.

    True.

    For any line, there are an infinite number of ways of writing its equation in vector form.

    This is because there are an infinite number of choices for the vectors bold italic aand bold italic b.

  • True or False?

    A line passes through the points with position vectors bold italic a and bold italic b. A possible equation of the line is bold italic r equals bold italic b bold minus bold italic a plus lambda bold italic b.

    False.

    A line passes through the points with position vectors bold italic a and bold italic b. A possible equation of the line is bold italic r equals bold italic a plus lambda open parentheses bold italic b minus bold italic a close parentheses.

    Other options are bold italic r equals bold italic a plus lambda open parentheses bold italic a minus bold italic b close parentheses, bold italic r equals bold italic b plus lambda open parentheses bold italic b minus bold italic a close parentheses and bold italic r equals bold italic b plus lambda open parentheses bold italic a minus bold italic b close parentheses.

  • If the equation of a line is given in vector form, how can you determine whether a given point lies on the line?

    If the equation of a line is given in vector form, you can determine whether a given point lies on the line by:

    • setting the equation of the line equal to the position vector of the point, bold italic a plus lambda bold italic b equals bold italic p,

    • forming three equations using the components of the vectors, e.g. a subscript 1 plus lambda b subscript 1 equals p subscript 1,

    • solving any of the equations to find value for lambda,

    • checking if this value satisfies the other two equations.

    If the value satisfies the other two equations then the point lies on the line.

  • The direction vector of a line is open parentheses table row l row m row n end table close parentheses and the position vector of a point that lies on the line is open parentheses table row cell x subscript 0 end cell row cell y subscript 0 end cell row cell z subscript 0 end cell end table close parentheses. What is the equation of the line in parametric form?

    The direction vector of a line is open parentheses table row l row m row n end table close parentheses and the position vector of a point that lies on the line is open parentheses table row cell x subscript 0 end cell row cell y subscript 0 end cell row cell z subscript 0 end cell end table close parentheses. The equation of the line in parametric form is

    table row x equals cell x subscript 0 plus lambda l end cell row y equals cell y subscript 0 plus lambda m end cell row z equals cell z subscript 0 plus lambda n end cell end table

    This is given in the formula booklet.

  • How do you find the angles between two lines?

    The angles between two lines can be found by finding the angles between a direction vector of one line and a direction vector of the other line. You can use the scalar product to do this.

  • True or False?

    One angle between a line (bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1) and another line (bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2) is given by the equation cos theta equals fraction numerator bold italic b subscript bold 1 times bold italic b subscript bold 2 over denominator open vertical bar bold italic b subscript bold 1 close vertical bar open vertical bar bold italic b subscript bold 2 close vertical bar end fraction.

    True.

    One angle between a line (bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1) and another line (bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2) is given by the equation cos theta equals fraction numerator bold italic b subscript bold 1 times bold italic b subscript bold 2 over denominator open vertical bar bold italic b subscript bold 1 close vertical bar open vertical bar bold italic b subscript bold 2 close vertical bar end fraction.

  • How do you find the shortest distance between a point, P, and a line, bold italic r bold space equals bold space bold italic a plus straight lambda bold italic b?

    To find the shortest distance between a point, P, and a line, bold italic r bold space equals bold space bold italic a plus straight lambda bold italic b, you

    • let F be the point on the line closest to P, bold italic f equals bold italic a plus lambda subscript 0 bold italic b,

    • find a displacement vector equation from F to P,

    • form an equation by making the scalar product of this displacement vector and direction vector of the line equal to zero,

    • find the value of lambda subscript 0by solving the equation,

    • substitute the value of lambda subscript 0 into the displacement vector and find the magnitude.

  • True or False?

    If a line passes through the point A and has direction vector bold italic b, then the shortest distance from the line to the point P is fraction numerator open vertical bar stack A P with rightwards arrow on top cross times bold italic b close vertical bar blank over denominator open vertical bar bold italic b close vertical bar end fraction.

    True.

    If a line passes through the point A and has direction vector bold italic b, then the shortest distance from the line to the point P is fraction numerator open vertical bar stack A P with rightwards arrow on top cross times bold italic b close vertical bar blank over denominator open vertical bar bold italic b close vertical bar end fraction.

    This formula is not given in the formula booklet.

  • How do you find the shortest distance between two parallel lines?

    To find the shortest distance between two parallel lines:

    • pick a point on one of the lines,

    • find the shortest distance between this point and the other line.

  • How do you find the shortest distance between to skew lines bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1 and bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2?

    To find the shortest distance between to skew lines bold italic r equals bold italic a subscript 1 plus lambda bold italic b subscript 1 and bold italic r equals bold italic a subscript 2 plus mu bold italic b subscript 2, you:

    • find an expression for the displacement between a general point on each line, open parentheses bold italic a subscript 1 plus lambda bold italic b subscript 1 close parentheses minus open parentheses bold italic a subscript 2 plus mu bold italic b subscript 2 close parentheses,

    • find the vector product of the two direction vectors, bold italic b subscript 1 cross times bold italic b subscript 2,

    • multiply the vector product by a constant k and set it equal to the displacement vector,

    • solve the simultaneous equations to find the value of k,

    • the shortest distance is open vertical bar k close vertical bar open vertical bar bold italic b subscript 1 cross times bold italic b subscript 2 close vertical bar.