Maclaurin Series from Differential Equations (DP IB Maths: AA HL)

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Maclaurin Series for Differential Equations

Can I apply Maclaurin Series to solving differential equations?

  • If you have a differential equation of the form fraction numerator d y over denominator d x end fraction equals g left parenthesis x comma y right parenthesis along with the value of y left parenthesis 0 right parenthesis it is possible to build up the Maclaurin series of the solution y equals f left parenthesis x right parenthesis term by term
    • This does not necessarily tell you the explicit function of x that corresponds to the Maclaurin series you are finding
    • But the Maclaurin series you find is the exact Maclaurin series for the solution to the differential equation
  • The Maclaurin series can be used to approximate the value of the solution y = f(x) for different values of x
    • You can increase the accuracy of this approximation by calculating additional terms of the Maclaurin series for higher powers of x

How can I find the Maclaurin Series for the solution to a differential equation?

  • STEP 1: Use implicit differentiation to find expressions for y apostrophe apostrophe comma space y apostrophe apostrophe apostrophe etc., in terms of x comma space y and lower-order derivatives of y 
    • The number of derivatives you need to find depends on how many terms of the Maclaurin series you want to find
    • For example, if you want the Maclaurin series up to the  term, then you will need to find derivatives up to y to the power of left parenthesis 4 right parenthesis end exponent (the fourth derivative of y)
  • STEP 2: Using the given initial value for y left parenthesis 0 right parenthesis, find the values of y apostrophe left parenthesis 0 right parenthesis comma space y apostrophe apostrophe left parenthesis 0 right parenthesis comma space y apostrophe apostrophe apostrophe left parenthesis 0 right parenthesis comma etc., one by one 
    • Each value you find will then allow you to find the value for the next higher derivative
  • STEP 3: Put the values found in STEP 2 into the general Maclaurin series formula

f left parenthesis x right parenthesis equals f left parenthesis 0 right parenthesis plus x f apostrophe left parenthesis 0 right parenthesis plus fraction numerator x squared over denominator 2 factorial end fraction f apostrophe apostrophe left parenthesis 0 right parenthesis plus...

    • This formula is in your exam formula booklet
    • y equals f left parenthesis x right parenthesis is the solution to the differential equation, so y left parenthesis 0 right parenthesis corresponds to f left parenthesis 0 right parenthesis in the formula, y apostrophe left parenthesis 0 right parenthesis corresponds to f apostrophe left parenthesis 0 right parenthesis, and so on
  • STEP 4: Simplify the coefficients for each of the powers of x in the resultant Maclaurin series

Worked example

Consider the differential equation y apostrophe equals y squared minus x with the initial condition y left parenthesis 0 right parenthesis equals 2.

a)
Use implicit differentiation to find expressions for y apostrophe apostrophe, y apostrophe apostrophe apostrophe and y to the power of left parenthesis 4 right parenthesis end exponent.

5-11-2-ib-aa-hl-maclaurin-series-from-diff-eqns-a-we-solution

b)
Use the given initial condition to find the values of y apostrophe left parenthesis 0 right parenthesis comma space y apostrophe apostrophe left parenthesis 0 right parenthesis comma space y apostrophe apostrophe apostrophe left parenthesis 0 right parenthesis and y to the power of left parenthesis 4 right parenthesis end exponent equals 0.

5-11-2-ib-aa-hl-maclaurin-series-from-diff-eqns-b-we-solution

Let y equals f left parenthesis x right parenthesis be the solution to the differential equation with the given initial condition.

c)
Find the first five terms of the Maclaurin series for f left parenthesis x right parenthesis.

5-11-2-ib-aa-hl-maclaurin-series-from-diff-eqns-c-we-solution

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