Complex Numbers (DP IB Maths: AA HL)

Topic Questions

4 hours33 questions
1a
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2 marks

Consider the complex numbers z subscript 1 equals 2 plus 2 straight iand z subscript 2 equals 2 plus 2 square root of 3 straight i.

Sketch z subscript 1and z subscript 2on the Argand diagram below, be sure to include an appropriate scale.

q1a_1-8_complex-numbers_medium_ib-maths-aa-hl

 

1b
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3 marks

Find the modulus of z subscript 1and z subscript 2.

1c
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3 marks

Find the argument of z subscript 1and z subscript 2.

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2
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7 marks

Solve the following equations for x

(i)
x squared plus 4 x plus 5 equals 0

(ii)
x squared equals negative 625

(iii)
x to the power of 4 equals 24 space minus space 2 x squared.

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3a
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2 marks

Let w subscript 1 equals z subscript 1 z subscript 2, where z subscript 1 equals 5 plus straight iand z subscript 2 equals 1 plus 2 straight i.

Express win the form w equals a plus b straight i.

3b
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4 marks

Find the modulus and argument for w

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4a
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3 marks

Let z equals w subscript 1 over w subscript 2, where w subscript 1 equals 4 minus straight i and w subscript 2 equals 1 minus 2 straight i.

Express zin the form z equals a plus b straight i.

4b
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4 marks

Find the modulus and argument for z.

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5a
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2 marks

Consider the complex numbers z equals 3 minus 4 straight i and w equals 7 minus 2 straight i.

Find 

(i)
z plus w

(ii)
w minus z.

5b
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2 marks

Let z to the power of asterisk timesand w to the power of asterisk timesrepresent the complex conjugates of z and w, respectively.

Write down z to the power of asterisk timesand w to the power of asterisk times, giving your answers in the form a plus b straight i.

5c
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4 marks

Find

(i)
z to the power of asterisk times w

(ii)
w to the power of asterisk times over z.

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6
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7 marks

Find all possible real values for a and bsuch that 

(i)
a plus b straight i equals 8 straight i

(ii)
open parentheses 2 plus 3 straight i close parentheses open parentheses a plus b straight i close parentheses equals 13

(iii)
open parentheses a plus straight i close parentheses open parentheses 2 plus b straight i close parentheses equals negative 6 plus 22 straight i.

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7
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7 marks

Consider the complex numbers w equals straight i zand w plus 2 z equals 7 plus 6 straight i.

Find

(i)
Re left parenthesis w right parenthesis

(ii)
Im left parenthesis w right parenthesis

(iii)
Re left parenthesis z right parenthesis

(iv)
Im left parenthesis z right parenthesis.

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8
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7 marks

It is given that z subscript 1 equals 3 plus 4 straight iand z subscript 2 equals negative 2 plus 2 straight i.

Find

(i)
straight i z subscript 1 plus z subscript 2

(ii)
fraction numerator z subscript 1 over denominator straight i z subscript 2 end fraction

(iii)
straight i left parenthesis z subscript 1 z subscript 2 right parenthesis.

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9
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8 marks

Find the complex numbers z and wsuch that 

2 z minus straight i w to the power of asterisk times equals 5 plus 7 straight i 

w plus straight i z to the power of asterisk times equals 5 plus 16 straight i

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10a
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5 marks

Let z equals 3 plus 8 straight iand w equals 4 minus 4 straight i.

Find theta, the angle shown on the diagram below.

q10a_1-8_complex-numbers_medium_ib-maths-aa-hl

10b
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3 marks

Find the area of the triangle formed in the diagram above.

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11a
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2 marks

Let z equals negative 1 minus 3 straight i and w equals 1 plus straight i.

Find z w.

11b
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3 marks

Sketch z comma w space and space space z w spaceon the Argand diagram below.

q11b_1-8_complex-numbers_medium_ib-maths-aa-hl

11c
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4 marks

Let theta be the angle between z and z wand ϕ be the angle between w and z w.

Find the angles thetaand ϕ, giving your answers in degrees.

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12a
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4 marks

Let w equals fraction numerator z plus 1 over denominator z to the power of asterisk times plus 1 end fraction, where z equals a plus b straight i comma space a comma space b element of straight real numbers.

Write win the form x plus y straight i comma space x comma space y element of straight real numbers. space

12b
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3 marks

Determine the conditions under which w is purely imaginary.

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1a
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3 marks

Consider the quadratic equation z squared minus 8 z plus 25 equals 0 comma space z element of straight complex numbers

The roots of the equation are  z subscript 1 equals a plus b straight i and  z subscript 2 equals a minus b straight i where a comma b element of straight integer numbers. 

Find the value of aand b.

1b
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4 marks

Sketch z subscript 1 comma space z subscript 2 comma space z subscript 1 plus z subscript 2and z subscript 1 minus z subscript 2 on the Argand diagram below, be sure to include an appropriate scale.

q1b-1-8-ib-aa-hl-complex-numbers-hard-maths_dig

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2
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7 marks

Consider the complex numbers  z subscript 1 equals negative 3 plus 2 straight iand z subscript 2 equals 1 minus 3 straight i.

Find

(i)
z subscript 1 plus z subscript 2
(ii)
z subscript 1 minus z subscript 2
(iii)
z subscript 1 z subscript 2
(iv)
z subscript 1 over z subscript 2

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3
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7 marks

Consider the complex numbers z subscript 1 equals 3 minus straight iand  z subscript 2 equals negative 2 minus 3 straight i. 

Find the modulus and argument of z subscript 1 z subscript 2 to the power of asterisk times.

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4a
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6 marks

Consider the complex numbers z subscript 1 equals 1 minus 2 straight i and z subscript 2 equals negative 3 plus 5 straight i.   

Work out the following:

(i)
Re open parentheses straight z subscript 2 minus straight z subscript 1 close parentheses
(ii)
Im open parentheses z subscript 1 z subscript 2 close parentheses
(iii)
open parentheses z subscript 1 over z subscript 2 close parentheses to the power of asterisk times

For part (iii) give your answer in the form a plus b straight i,  where a and b are real numbers.

4b
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2 marks

Write down the complex conjugate of z subscript 2and describe the geometrical relationship between z subscript 2 and z subscript 2 to the power of asterisk times.

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5
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7 marks

Find all possible real values for a and b such that

(i)
open parentheses a plus b straight i close parentheses open parentheses 2 minus 3 straight i close parentheses equals 8 plus straight i
(ii)
a open parentheses 2 plus b straight i close parentheses equals b open parentheses negative 6 plus straight i close parentheses
(iii)
open parentheses 2 a plus 3 straight i close parentheses open parentheses 3 plus b straight i close parentheses equals 12 plus 21 straight i

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6a
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3 marks

For a general complex number z equals x plus straight i y,  where x comma y element of straight real numbers,  show that

(i)
Re open parentheses z close parentheses equals fraction numerator z plus z italic asterisk times over denominator 2 end fraction
(ii)
Im open parentheses z close parentheses equals fraction numerator z minus z to the power of asterisk times over denominator 2 straight i end fraction

 

6b
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6 marks

For the complex numbers z subscript 1 equals a subscript 1 plus b subscript 1 straight iand z subscript 2 equals a subscript 2 plus b subscript 2 straight i,  where  a subscript 1 comma space a subscript 2 comma space b subscript 1 comma space b subscript 2 element of straight real numbers, show that

open vertical bar z subscript 1 z subscript 2 close vertical bar equals open vertical bar z subscript 1 close vertical bar open vertical bar z subscript 2 close vertical bar

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7
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8 marks

Consider the complex numbers w equals 2 straight i z and w minus z equals 5 minus 5 straight i.

Find

(i)
open vertical bar z close vertical bar
(ii)
arg space w
(iii)
Re open parentheses z plus w close parentheses
(iv)
Im open parentheses z minus w close parentheses

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8a
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4 marks

Consider the complex numbers z subscript 1 equals a minus 6 straight i comma space straight z subscript 2 equals 1 plus b straight i and z subscript 1 z subscript 2 equals negative 17 minus 9 straight iwhere a comma space b element of straight real numbers

Find the possible values of aand b.

8b
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2 marks

Using the answers gained in part (a), write down values for cand dthat will satisfy the equation

negative open parentheses 3 plus straight i close parentheses open parentheses c plus d straight i close parentheses equals 17 minus 9 straight i

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9a
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2 marks

Consider the complex numbers z equals 3 plus 5 straight i space and space w equals negative 2 plus 3 straight i

Represent the complex numbers z and won an Argand diagram.

9b
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5 marks

The points z plus w and z minus ware represented by the points straight Aand straight Bon the Argand diagram respectively.

Find the angle straight A straight O with hat on top straight B.

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10a
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4 marks

Consider the complex numbers z equals negative 4 minus 3 straight i comma space w equals a iand  z over w equals b plus 2 a straight i, where a comma space b element of straight real numbers.

Find the possible values of aand b.

10b
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3 marks

Find the modulus of w over z.

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11a
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4 marks

Let omega subscript 1 equals 3 minus straight i space and space omega subscript 2 equals 1 plus 2 straight i.

Given that 1 over omega subscript 1 plus 1 over omega subscript 2 equals 1 over z, express zin the form a plus b straight i, where a comma b element of straight real numbers.

11b
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2 marks

Find omega subscript 1 omega subscript 2 z to the power of asterisk times, giving your answer in the form a plus b straight i, where a comma space b element of straight real numbers.

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1a
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4 marks

Consider the complex numbers z subscript 1 equals square root of 3 plus 2 straight iand z subscript 2 equals straight i minus 3 square root of 3.

Find

(i)
u equals z subscript 1 z subscript 2
(ii)
v equals z subscript 1 over z subscript 2
1b
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3 marks

The complex numbers uand v are represented by the points straight Aand straight Brespectively on an Argand diagram with origin straight O. 

Determine whether the angle made by OAwith the positive horizontal axis is greater than or less than the angle made by OBwith the positive horizontal axis. Give a reason for your answer.

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2a
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4 marks

Consider the complex number z equals negative a plus 3 over 4 straight i.

Write down, in terms of a,

(i)
Re open parentheses z to the power of italic 2 close parentheses
(ii)
Im open parentheses z to the power of italic 3 close parentheses
2b
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4 marks

In the case where a equals 2, find the modulus and argument of z cubed.

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3a
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3 marks

Consider the complex numbers  z subscript 1 equals straight i minus 1 half and z subscript 2 equals 1 half minus 3 over straight i.

Express z subscript 2 in the form a plus b straight i, where a comma b element of straight real numbers.

3b
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6 marks

Find

(i)
z subscript 1 to the power of asterisk times z subscript 2
(ii)
z subscript 2 over z subscript 1
(iii)
open vertical bar z subscript 2 over z subscript 1 close vertical bar, giving your answer as an exact value.

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4
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6 marks

Consider a general complex number z equals x plus straight i y,  where  x comma space y element of straight real numbers , z element of straight complex numbers and  z not equal to 0

Show that

(i)
Re open parentheses 1 over straight z plus 1 over straight z to the power of asterisk times close parentheses equals fraction numerator 2 x over denominator x to the power of italic 2 plus y to the power of italic 2 end fraction
(ii)
Im open parentheses 1 over z plus 1 over z to the power of italic asterisk times close parentheses equals 0
(iii)
z z to the power of asterisk times equals open vertical bar z close vertical bar squared

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5a
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4 marks

Consider the equation z w minus w plus straight i z plus 1 equals 0, where w comma space z element of straight complex numbersw equals x plus straight i y.

Find an expression in terms of xand yfor Re open parentheses z close parentheses.

5b
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4 marks

Find in terms of x given that z is purely real.

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6a
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5 marks

Consider the complex numbers z subscript 1 equals fraction numerator 3 minus straight i over denominator 1 minus 2 straight i end fractionand z subscript 2 equals negative 3 straight i plus 1. 

Find the modulus of z subscript 1 over z subscript 2 to the power of asterisk times  giving your answer as an exact value.

6b
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2 marks

The argument of z subscript 1 over z subscript 2 to the power of asterisk timesis given as theta equals tan to the power of negative 1 end exponent x, where 0 less than theta less than 2 straight pi.  Find the value of x.

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7a
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3 marks

Consider the complex numbers z equals v over w comma v equals 1 minus p i space and space straight w equals 3 straight i minus 2 

Express z in the form a plus b straight i, where a comma space b comma space p element of straight real numbers..

7b
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4 marks

In the case where z is purely imaginary, represent v comma space wand zon an Argand diagram.

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8a
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4 marks

Consider the complex numbers z equals fraction numerator a minus 3 straight i over denominator 2 plus straight i end fraction comma space w equals a plus b text i end textand z over w equals 1 plus 2 straight i where a comma space b element of straight real numbers.

Find the values of a and b.

8b
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2 marks

Find the modulus of w over z, giving your answer as an exact value.

8c
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2 marks

Find the argument of w over z, giving your answer in the range negative straight pi less or equal than arg w over z less or equal than pi  .

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9
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7 marks

Consider the complex numbers a minus w equals 2 z minus straight iand w minus 2 z equals b straight i minus 1

Find the values of aand bsuch that Re open parentheses w close parentheses equals Im open parentheses z close parenthesesand Re open parentheses w close parentheses equals Re open parentheses z close parentheses plus 1.

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10a
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3 marks

Consider the complex numbers z subscript 1 equals 5 plus p straight i, z subscript 2 equals a plus b straight i and z subscript 1 over z subscript 2 equals negative 1 plus straight i, where z element of straight complex numbers
and a comma space b element of straight real numbers.

Find the values of aand b in terms of p

10b
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3 marks

Given that open vertical bar z subscript 2 close vertical bar equals square root of 73, find the possible values of p.

10c
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2 marks

Given additionally that arg open parentheses z subscript 2 close parentheses equals 2.78 radians correct to 2 decimal places, determine the exact value of Im open parentheses z subscript 2 close parentheses.

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