Coordinate Geometry (DP IB Maths: AI HL)

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Amber

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Amber

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Basic Coordinate Geometry

What are cartesian coordinates?

  • Cartesian coordinates are basically the x-y coordinate system
    • They allow us to label where things are in a two-dimensional plane
  • In the 2D cartesian system, the horizontal axis is labelled x and the vertical axis is labelled y

 

What can we do with coordinates?

  • If we have two points with coordinates (x1 , y1) and (x2 , y2) then we should be able to find
    • The midpoint of the two points
    • The distance between the two points
    • The gradient of the line between them

 

How do I find the midpoint of two points?

  • The midpoint is the average (middle) point
    • It can be found by finding the middle of the x-coordinates and the middle of the y-coordinates
  • The coordinates of the midpoint will be

begin mathsize 22px style open parentheses fraction numerator x subscript 1 plus blank x subscript 2 over denominator 2 end fraction blank comma blank fraction numerator y subscript 1 plus blank y subscript 2 over denominator 2 end fraction blank close parentheses end style

    • This is given in the formula booklet under the prior learning section at the beginning

Basic Coordinate Geometry Notes Diagram 5

How do I find the distance between two points?

  • The distance between two points with coordinates (x1 , y1) and (x2 , y2) can be found using the formula

begin mathsize 22px style d space equals blank square root of open parentheses x subscript 1 minus blank x subscript 2 close parentheses squared space plus space open parentheses y subscript 1 minus blank y subscript 2 close parentheses squared end root blank end style

    • This is given in the formula booklet in the prior learning section at the beginning
  • Pythagoras’ Theorem a squared space equals space b squared plus c squared  is used to find the length of a line between two coordinates
  • If the coordinates are labelled A and B then the line segment between them is written with the notation [AB]

Basic Coordinate Geometry Notes Diagram 2

How do I find the gradient of the line between two points?

  • The gradient of a line between two points with coordinates (x1 , y1) and (x2 , y2) can be found using the formula

begin mathsize 22px style m equals blank fraction numerator y subscript 2 minus blank y subscript 1 over denominator x subscript 2 minus blank x subscript 1 end fraction end style

    • This is given in the formula booklet under section 2.1 Gradient formula
    • This is usually known as  m equals rise over run

Worked example

Point A has coordinates (3, -4) and point B has coordinates (-5, 2).

i)
Calculate the distance of the line segment AB.

ai-sl-3-1-1-basic-cg-we-i

ii)
Find the gradient of the line connecting points A and B.

 ai-sl-3-1-1-basic-cg-we-ii

iii)
Find the midpoint of [AB ] .

ai-sl-3-1-1-basic-cg-we-iii

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Perpendicular Bisectors

What is a perpendicular bisector?

  • A perpendicular bisector of a line segment cuts the line segment in half at a right angle
    • Perpendicular lines meet at right angles
    • Bisect means to cut in half
  • Two lines are perpendicular if the product of their gradients is -1

 

How do I find the equation of the perpendicular bisector of a line segment?

  • To find the equation of a straight line you need to find
    • The gradient of the line
    • A coordinate of a point on the line
  • To find the equation of the perpendicular bisector of a line segment follow these steps:
    • STEP 1: Find the coordinates of the midpoint of the line segment
      • We know that the perpendicular bisector will cut the line segment in half so we can use the midpoint of the line segment as the known coordinate on the bisector
    • STEP 2: Find the gradient of the line segment
    • STEP 3: Find the gradient of the perpendicular bisector
      • This will be -1 divided by the gradient of the line segment
    • STEP 4: Substitute the gradient of the perpendicular bisector and the coordinates of the midpoint into an equation for a straight line
      • The point-gradient form bold italic y minus blank bold italic y subscript 1 blank end subscript equals bold italic m bold space left parenthesis bold italic x minus blank bold italic x subscript 1 right parenthesisis the easiest
    • STEP 5: Rearrange into the required form
      • Either y space equals space m x space plus space c  or  a x space plus space b y space plus thin space d space equals space 0 
      • These equations for a straight line are given in the formula booklet

Worked example

Point A has coordinates (4, -6) and point B has coordinates (8, 6).  Find the equation of the perpendicular bisector to [AB ]. Give your answer in the form a x space plus space b y space plus space d space equals space 0.

ai-sl-3-1-1-perp-bis-we

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Amber

Author: Amber

Amber gained a first class degree in Mathematics & Meteorology from the University of Reading before training to become a teacher. She is passionate about teaching, having spent 8 years teaching GCSE and A Level Mathematics both in the UK and internationally. Amber loves creating bright and informative resources to help students reach their potential.