Magnetic Force on a Current-Carrying Conductor
- A current-carrying conductor produces its own magnetic field
- When interacting with an external magnetic field, it will experience a force
- The force F on a conductor carrying current I at an angle θ to a magnetic field with flux density B is defined by the equation
- Where:
- F = force on a current-carrying conductor in a B field (N)
- B = magnetic flux density of applied B field (T)
- I = current in the conductor (A)
- L = length of the conductor (m)
- θ = angle between the conductor and applied B field (degrees)
- This equation shows that the force on the conductor can be increased by:
- Increasing the strength of the magnetic field
- Increasing the current flowing through the conductor
- Increasing the length of the conductor in the field
- Note: The length L represents the length of the conductor that is within the field
The magnitude of the force on a current-carrying conductor depends on the angle of the conductor to the external B field
- A current-carrying conductor (e.g. a wire) will experience the maximum magnetic force if the current through it is perpendicular to the direction of the magnetic field lines
- It experiences no force if it is parallel to magnetic field lines
- The maximum force occurs when sin θ = 1
- This means θ = 90° and the conductor is perpendicular to the B field
- The equation for the magnetic force becomes:
- The minimum force, i.e. F = 0 N, is when sin θ = 0°
- This means θ = 0° and the conductor is parallel to the B field
- It is important to note that a current-carrying conductor will experience no force if the current in the conductor is parallel to the field
- This is because the F, B and I must be perpendicular to each other
Observing the Force on a Current-Carrying Conductor
- The force due to a magnetic field can be observed by
- placing a copper rod in a uniform magnetic field
- connecting the copper rod to a circuit
- When current is passed through the copper rod, it experiences a force
- This causes it to accelerate in the direction of the force
A copper rod moves within a magnetic field when current is passed through it
Worked example
A current of 0.87 A flows in a wire of length 1.4 m placed at 30° to a magnetic field of flux density 80 mT.
Calculate the force on the wire.
Answer:
Step 1: Write down the known quantities
- Magnetic flux density, B = 80 mT = 80 × 10−3 T
- Current, I = 0.87 A
- Length of wire, L = 1.4 m
- Angle between the wire and the magnetic field, θ = 30°
Step 2: Write down the equation for force on a current-carrying conductor
Step 3: Substitute in values and calculate
F = (80 × 10-3) × (0.87) × (1.4) × sin(30) = 0.04872 = 0.049 N (2 s.f)
Exam Tip
Remember that the direction of current flow is the flow of positive charge (positive to negative), and this is in the opposite direction to the flow of electrons