Magnetic Force on a Charge
- A moving charge produces its own magnetic field
- When interacting with an applied magnetic field, it will experience a force
- The force F on an isolated particle with charge Q moving with speed v at an angle θ to a magnetic field with flux density B is defined by the equation
- Where:
- F = magnetic force on the particle (N)
- B = magnetic flux density (T)
- q = charge of the particle (C)
- v = speed of the particle (m s−1)
- Current is taken as the rate of flow of positive charge (i.e. conventional current)
- This means that the direction of the current for a flow of negative charge (e.g. a beam of electrons) is in the opposite direction to its motion
- As with a current-carrying conductor, the maximum force on a charged particle occurs when it travels perpendicular to the field
- This is when θ = 90°, so sin θ = 1
- The equation for the magnetic force becomes:
- F, B and v are mutually perpendicular, therefore:
- If the direction of the particle's motion changes, the magnitude of the force will also change
- If the particle travels parallel to a magnetic field, it will experience no magnetic force
The force on an isolated moving charge is perpendicular to its motion and the magnetic field B
- From the diagram above, when a beam of electrons enters a magnetic field which is directed into the page:
- Electrons are negatively charged, so current I is directed to the right (as motion v is directed to the left)
- Using Fleming’s left hand rule, the force on an electron will be directed upwards
Worked example
An electron moves in a uniform magnetic field of flux density 0.2 T at a velocity of 5.3 × 107 m s−1.
Answer:
(a)
Step 1: Write out the known quantities
- Velocity of the electron, v = 5.3 × 107 m s−1
- Charge of an electron, q = 1.60 × 10−19 C
- Magnetic flux density, B = 0.2 T
Step 2: Write down the equation for the magnetic force on an isolated particle
- The electron moves perpendicular (θ = 90°) to the field, so sin θ = 1
Step 3: Substitute in values, and calculate the force on the electron
F = (0.2) × (1.60 × 10−19) × (5.3 × 107) = 1.7 × 10−12 N (2 s.f.)
(b)
Step 1: Write an expression for the ratio of the two forces
- When the electron moves perpendicular to the field:
- When the electron moves at angle θ to the field:
- The ratio of these forces is
Step 2: Determine the angle when the ratio of the forces is equal to one-half
- When the force halves, the ratio is
- The angle this occurs at is
Exam Tip
Remember not to mix this up with F = BIL!
- F = BIL is for a current-carrying conductor
- F = Bqv is for an isolated moving charge (which may be inside a conductor)